Bihar School Examination Board (BSEB) Class 8 Mathematics: Factorisation

4 multiple-choice questions with answer key for Bihar School Examination Board (BSEB) Class 8 Mathematics – Factorisation, Rational Numbers, Squares and…

  • 4 questions · 4 marks
  • 15 minutes
  • 4 options (A–D)
  • English
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Bihar School Examination Board (BSEB) Class 8 Mathematics: Factorisation

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Bihar School Examination Board (BSEB) Class 8 Mathematics: Factorisation
Class 8 · Mathematics · 4 questions · 4 marks · 15 minutes

Instructions. Answer all questions. Fill exactly one bubble per question on the OMR sheet.

  1. Factorisation

    1.

    Factorise 12a2b+15ab212a^2b + 15ab^2.

    1. (A)

      3a(4ab+5b2)3a(4ab + 5b^2)

    2. (B)

      3b(4a2+5ab)3b(4a^2 + 5ab)

    3. (C)

      ab(12a+15b)ab(12a + 15b)

    4. (D)

      3ab(4a+5b)3ab(4a + 5b)

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    Answer: (D)

    3ab(4a+5b)3ab(4a + 5b)

    To factorise 12a2b+15ab212a^2b + 15ab^2, find the greatest common factor (GCF) of the terms. The GCF of 12a2b12a^2b and 15ab215ab^2 is 3ab3ab. Dividing each term by 3ab3ab gives 4a4a and 5b5b respectively, so the factorised form is 3ab(4a+5b)3ab(4a + 5b).

    Factorisation · Easy

  2. 2.

    Factorise x2+8x+16x^2 + 8x + 16.

    1. (A)

      (x+4)2(x + 4)^2

    2. (B)

      (x+4)(x−4)(x + 4)(x - 4)

    3. (C)

      (x+8)(x+2)(x + 8)(x + 2)

    4. (D)

      (x−4)2(x - 4)^2

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    Answer: (A)

    (x+4)2(x + 4)^2

    The expression x2+8x+16x^2 + 8x + 16 is a perfect square trinomial because it matches the form a2+2ab+b2a^2 + 2ab + b^2, where a=xa = x and b=4b = 4. Thus, it factorises to (x+4)2(x + 4)^2.

    Factorisation · Medium

  3. 3.

    Factorise 49p2−36q249p^2 - 36q^2.

    1. (A)

      (49p−36q)(p+q)(49p - 36q)(p + q)

    2. (B)

      (7p+6q)2(7p + 6q)^2

    3. (C)

      (7p−6q)2(7p - 6q)^2

    4. (D)

      (7p+6q)(7p−6q)(7p + 6q)(7p - 6q)

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    Answer: (D)

    (7p+6q)(7p−6q)(7p + 6q)(7p - 6q)

    The expression 49p2−36q249p^2 - 36q^2 is in the form of a difference of squares, a2−b2=(a−b)(a+b)a^2 - b^2 = (a - b)(a + b). Here, a=7pa = 7p and b=6qb = 6q. Therefore, the factorised form is (7p+6q)(7p−6q)(7p + 6q)(7p - 6q).

    Factorisation · Medium

  4. 4.

    Factorise 5x2−20x5x^2 - 20x.

    1. (A)

      5(x2−4x)5(x^2 - 4x)

    2. (B)

      5x(x−4)5x(x - 4)

    3. (C)

      x(5x−20)x(5x - 20)

    4. (D)

      5x(x+4)5x(x + 4)

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    Answer: (B)

    5x(x−4)5x(x - 4)

    To factorise 5x2−20x5x^2 - 20x, find the greatest common factor (GCF) of the terms. The GCF of 5x25x^2 and 20x20x is 5x5x. Dividing each term by 5x5x gives xx and −4-4 respectively, so the factorised form is 5x(x−4)5x(x - 4).

    Factorisation · Easy

— End of the paper · updated 14 October 2026 —